수상포집. 27.0℃ 750 torr 37.5 mL 0.0873 g P_H2O 26.98 torr

수상포집. 27.0℃ 750 torr 37.5 mL 0.0873 g P_H2O 26.98 torr

 

 

An unknown gas was collected by water displacement.

The following data was recorded:

T = 27.0℃; P = 750 torr; V = 37.5 mL;

Gas mass = 0.0873 g; P_vap(H2O) = 26.98 torr

Determine the molecular weight of the gas.

 

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기체의 압력 = 750 – 26.98 = 723.02 torr

( 참고 https://ywpop.tistory.com/3490 )

 

 

 

PV = nRT

 

n = PV / RT

= [(723.02/760) (37.5/1000)] / [(0.08206) (273.15 + 27.0)]

= 0.0014484 mol

 

 

 

0.0873 g / 0.0014484 mol

= 60.27 g/mol

( 참고 https://ywpop.tistory.com/7738 )

 

 

 

답: 60.3 g/mol

 

 

 

 

[키워드] 수상치환 기준문서, 수상포집 기준문서