1.00% light speed velocity de Broglie 3.31×10^(-3) pm element

1.00% light speed velocity de Broglie 3.31×10^(-3) pm element

 

 

An atom of a particular element is traveling at 1.00% of the speed of light.

The de Broglie wavelength is found to be 3.31×10^(-3) pm.

Which element is this?

 

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(3.31×10^(-3) pm) (1 m / 10^12 pm) = 3.31×10^(-15) m

 

 

 

λ = h / mc

( 참고 https://ywpop.tistory.com/3265 )

 

m = h / cλ

= (6.626×10^(-34) kg•m^2/s) / [(2.998×10^8 m/s) (1.00/100) (3.31×10^(-15) m)]

= (6.626×10^(-34)) / [(2.998×10^8) (1.00/100) (3.31×10^(-15))]

= 6.677×10^(-26) kg

---> 1개 원자의 질량

 

 

 

(6.677×10^(-26) kg) (1000 g / 1 kg) (6.022×10^23 /mol)

= (6.677×10^(-26)) (1000) (6.022×10^23)

= 40.21 g/mol

---> 칼슘, Ca

 

 

 

답: Ca