본문 바로가기
화학/용액의 농도

NaOH 25.00 mL + 0.485 M HNO3 42.67 mL

by 영원파란 2021. 5. 12.

AdSense@ywpop

NaOH 25.00 mL + 0.485 M HNO3 42.67 mL

 

 

NaOH 25.00 mL 적정하는데

0.485 M HNO3 42.67 mL 사용되었다.

NaOH 용액의 농도는?

 

 

Analysis of a solution of NaOH showed that

42.67 mL of 0.485 M HNO3 was needed

to titrate a 25.00 mL sample of NaOH.

What is the concentration of the NaOH solution?

 

---------------------------------------------------

 

MV = M’V’

H^+의 몰수 = OH^-의 몰수

( 참고 https://ywpop.tistory.com/4689 )

 

(0.485 M) (42.67 mL) = (? M) (25.00 mL)

 

? = (0.485) (42.67) / (25.00) = 0.828 M

 

 

반응형
그리드형(광고전용)

댓글