How many moles of Fe2O3 will be produced from 18.0 g of Fe

How many moles of Fe2O3 will be produced from 18.0 g of Fe,

assuming O2 is available in excess?

4Fe + 3O2 → 2Fe2O3

 

 

18.0 g Fe와 과량의 O2를 반응시켰을 때 Fe2O3는 몇 mol 생성되겠는가?

 

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Fe의 몰질량 = 55.85 g/mol

18.0 g / (55.85 g/mol) = 0.322292 mol Fe

( 계산 설명 https://ywpop.tistory.com/7738 )

 

 

Fe : Fe2O3 = 2 : 1 계수비(= 몰수비) 이므로,

Fe : Fe2O3 = 2 : 1 = 0.322292 mol : ? mol

? = 0.322292 / 2 = 0.161146 mol Fe2O3

 

 

답: 0.161 mol