반응형 일반화학6126 ratio of [Hb(CO)] to [Hb(O2)] in air 20% O2 and 0.15% CO by volume ratio of [Hb(CO)] to [Hb(O2)] in air 20% O2 and 0.15% CO by volume The following reaction shows the equilibrium reactionthat occurs when carbon monoxide enters the blood.(Note: The K value uses partial pressures of O2and CO in the equilibrium expression.)Hb(O2)(aq) + CO(g) ⇌ Hb(CO)(aq) + O2(g) ... K = 207 at 37℃What is the ratio of [Hb(CO)] to [Hb(O2)]in air that contains 20% O2 and 0.15% C.. 2024. 10. 24. 분압과 농도, 둘 다 같은 평형상수 식에 있을 수 있는가? 분압과 농도, 둘 다 같은 평형상수 식에 있을 수 있는가? Can both partial pressure and concentrationbe in the same equilibrium constant equation? [참고] 평형상수 식[ https://ywpop.tistory.com/7136 ] Q. Can both partial pressure and concentrationbe in the same equilibrium constant equation? 분압과 농도, 둘 다 같은 평형상수 식에 있을 수 있는가?( 출처 https://www.quora.com/Can-both-partial-pressure-and-concentration-be-in-the-same.. 2024. 10. 24. O3 molecules 10 million cubic meters of air at 25℃ 720 mmHg O3 molecules 10 million cubic meters of air at 25℃ 720 mmHg Ozone is unstable with respect to decomposition to ordinary oxygen:2O3(g) ⇌ 3O2(g) ... Kp = 1.3×10^57How many O3 molecules are present at equilibriumin 10 million cubic meters of air at 25 ℃ and 720 mmHg pressure? 오존은 불안정하여 산소로 분해된다.2O3(g) ⇌ 3O2(g) ... Kp = 1.3×10^5725 ℃, 720 mmHg에서 평형 상태의 1000만 m3 공기 중에O3 분자는 얼마나 존재하는가? ---.. 2024. 10. 23. percentage of molecules dissociated freezing point 1.00 m CCl3CO2H –2.53℃ percentage of molecules dissociated freezing point 1.00 m CCl3CO2H –2.53℃ Like most acids, trichloroacetic acid dissociates into ions in aqueous solution as shown in the equation below.Many acids are partially dissociated into ions in aqueous solution. Trichloroacetic acid (CCl3CO2H), for instance, is partially dissociated in water according to the equation:CCl3CO2H(aq) ⇌ H^+(aq) + CCl3CO2^.. 2024. 10. 23. 3.00 mol of each component was added to a 1.50 L flask 3.00 mol of each component was added to a 1.50 L flask Assume that the reaction for the formation of gaseous hydrogen fluoride from hydrogen and fluorine has an equilibrium constant of 1.15×10^2 at a certain temperature. In a particular experiment, 3.00 mole of each component was added to a 1.50 L flask. Calculate the equilibrium concentrations of all species. 어떤 온도에서, 수소와 F2로부터 HF 기체를.. 2024. 10. 23. mixture KCl KNO3 Ba(NO3)2 20.92% Cl 1.000 g 500.0 mL 25℃ 744.7 mmHg mixture KCl KNO3 Ba(NO3)2 20.92% Cl 1.000 g 500.0 mL 25℃ 744.7 mmHg A solid mixture of KCl, KNO3, and Ba(NO3)2 is 20.92 mass % chlorine, and a 1.000 g sample of the mixture in 500.0 mL of aqueous solution at 25℃ has an osmotic pressure of 744.7 mmHg.What are the mass percents of KCl, KNO3, and Ba(NO3)2 in the mixture? KCl, KNO3, Ba(NO3)2의 고체 혼합물은 20.92 질량 % 염소를 포함하고, 25℃에서 이 혼합물 1.000 .. 2024. 10. 22. Which atom(s) contains a total of 5 valence electrons Which atom(s) contains a total of 5 valence electrons Which atom(s) contains a total of 5 valence electrons?1) V2) Sb3) N [참고] 주기율표 암기[ https://ywpop.tistory.com/4841 ] 주기율표 20번까지는암기하고 있으니,3) N---> 5A족 원소이므로,원자가 전자 수 = 5. 원자번호 23인 V,원자번호 51인 Sb,---> 필자도 모른다. 만약 open book test (open book exam) 이라면,주기율표를 보니,전이금속인 V의 전자배치: [Ar] 3d^3 4s^2---> 원자가 전자 수 = 5.( 참고 http.. 2024. 10. 22. pH of soft drink 10.0 g KH2PO4 and 10.0 g K2HPO4 per 0.500 L pH of soft drink 10.0 g KH2PO4 and 10.0 g K2HPO4 per 0.500 L A buffer, consisting of H2PO4^- and HPO4^2-, helps control the pH of physiological fluids. Many carbonated soft drinks also use this buffer system.What is the pH of a soft drink in which the major buffer ingredients are 10.0 g of KH2PO4 and 10.0 g of K2HPO4 per 0.500 L of solution? H2PO4^-와 HPO4^2-로 구성된 완충 용액은 생리학적 유체의 pH를 조절.. 2024. 10. 22. 전하 균형의 법칙. M + 2NO3^- + 4H^+ → M^x+ + 2NO2 + 2H2O 전하 균형의 법칙. M + 2NO3^- + 4H^+ → M^x+ + 2NO2 + 2H2O에서 x의 값은? [참고] 전하 균형의 법칙[ https://ywpop.tistory.com/16024 ] 균형 맞춘 반응식 같으니,“전하 균형의 법칙”으로 간단히 계산할 수 있다. 각 물질의 전하의 합은반응 전/후 같아야 하므로, M + 2NO3^- + 4H^+ → M^x+ + 2NO2 + 2H2O(0) + 2(–1) + 4(+1) = (+x) + 2(0) + 2(0) +2 = +x x = 2 답: x = 2 [ 관련 글 https://ywpop.tistory.com/4264 ]산화-환원 반응 균형 맞추기. 산성 용액에서 .. 2024. 10. 22. NH4Cl 2.00 L 0.500 M NH3 buffer pH 9.20 NH4Cl 2.00 L 0.500 M NH3 buffer pH 9.20 Calculate the number of grams of ammonium chloride that must be added to 2.00 L of a 0.500 M ammonia solution to obtain a buffer of pH = 9.20. Assume the volume of the solution does not change as the solid is added. Kb for ammonia is 1.80×10^(-5). pH 9.20의 완충 용액을 만들기 위해 0.500 M 암모니아 용액 2.00 L에 첨가해야 하는 염화 암모늄의 질량은 얼마인가? (용질을 첨가하여도 용액의 부피는 변하지 않는다고.. 2024. 10. 22. 이전 1 ··· 8 9 10 11 12 13 14 ··· 613 다음 반응형
