molar solubility of AgCl in 0.100 M NH3

molar solubility of AgCl in 0.100 M NH3

 

 

Calculate the molar solubility of AgCl (Ksp = 1.8e-10) in 0.100 M NH3 (Kf = 1.6e+7 for Ag(NH3)2^+).

 

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.. AgCl(s) ⇌ Ag^+(aq) + Cl^-(aq) ... Ksp = 1.8e-10

+) Ag^+(aq) + 2NH3(aq) ⇌ Ag(NH3)2^+(aq) ... Kf = 1.6e+7

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.. AgCl(s) + 2NH3(aq) ⇌ Ag(NH3)2^+(aq) + Cl^-(aq) ... Kc = 0.00288

 

 

Kc = (1.8e-10) × (1.6e+7) = 0.00288

( 참고 https://ywpop.tistory.com/4154 )

 

 

 

 

............ AgCl(s) + 2NH3(aq) ⇌ Ag(NH3)2^+(aq) + Cl^-(aq)

평형에서 .............. 0.100-2x .. x .............. x

 

 

Kc = [Ag(NH3)2^+][Cl^-] / [NH3]^2

= x^2 / (0.100-2x)^2 = 0.00288

 

 

 

(x / (0.100-2x))^2 = 0.00288

x / (0.100-2x) = (0.00288)^(1/2) = 0.0536656

x = 0.00536656 – 0.107331x

1.107331x = 0.00536656

 

x = 0.00536656 / 1.107331

= 0.00485 M = [Cl^-] = [AgCl]

 

 

 

답: 0.00485 M

 

 

 

 

[ 관련 예제 https://ywpop.tistory.com/8211 ] 1.0 M NH3에서 AgCl의 몰용해도

 

 

 

[키워드] AgCl의 몰용해도 기준문서, AgCl의 용해도 기준문서