pH 1.25인 약산 HClO2의 몰농도

pH 1.25인 약산 HClO2의 몰농도

 

 

Determine the molarity of a solution of the weak acid HClO2 (Ka=1.10×10^-2)

if it has a pH of 1.25.

 

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HClO2(aq) ⇌ H^+(aq) + ClO2^-(aq)

Ka = x^2 / C-x = 1.10×10^-2

C = [x^2 / (1.10×10^-2)] + x

 

pH = -log[H+] = 1.25

[H+] = 10^-1.25 = 0.0562 M = x

 

C = [(0.0562)^2 / (1.10×10^-2)] + 0.0562

= 0.343 M

 

답: 0.343 M