Calculate the volume (L) of 0.385 M manganese (ll) sulfate

Calculate the volume (L) of 0.385 M manganese (ll) sulfate

 

 

Calculate the volume (L) of 0.385 M manganese (ll) sulfate that contains 63.0 g solute.

 

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MnSO4의 몰질량 = 151 g/mol

63.0 g MnSO4의 몰수

= 63.0 g / (151 g/mol) = 0.417 mol

 

0.385 mol/L = 0.417 mol / ? L

? = 0.417 mol / (0.385 mol/L) = 1.083 L

 

답: 1.083 L