시스플라틴 285.3 g의 mol수

시스플라틴 285.3 g의 mol수

 

 

Cisplatin or Platinol has a chemical PtCl2(NH3)2 that is used in the treatment of certain cancers. Calculate (a) the amount (mol) of compound in 285.3 g of cisplatin; (b) the number of hydrogen atoms in 0.98 mol of cisplatin.

 

 

 

 

(a)

PtCl2(NH3)2의 몰질량 = 300.05 g/mol 이므로,

285.3 g / (300.05 g/mol)

= 0.9508 mol

( 참고 https://ywpop.tistory.com/7738 )

 

 

 

(b)

0.98 mol cisplatin × (6 mol H / 1 mol cisplatin)

= 0.98 × (6)

= 5.88 mol H

 

 

(5.88 mol) (6.022×10^23 개 / 1 mol)

= (5.88) (6.022×10^23)

= 3.54×10^24 개

또는

= 3.5×10^24 개

 

 

 

 

[키워드] 시스플라틴 기준, cisplatin dic, cisplatin 285.3 g 0.98 mol hydrogen atom