화학/용액의 농도
25.0 μL solution 26.7 μg solute concentration in ppm and mg/dL
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2024. 3. 25. 22:45
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25.0 μL solution 26.7 μg solute concentration in ppm and mg/dL
A 25.0 μL sample was found to contain 26.7 μg glucose. Express the concentration as ppm and mg/dL glucose.
25.0 μL 용액 중 용질의 질량이 26.7 μg인 용액의 농도를
ppm과 mg/dL 단위로 구하시오.
[참고] 환산 인자
[ https://ywpop.tistory.com/3121 ]
[참고] 미터법 접두어
[ https://ywpop.tistory.com/2328 ]
(25.0 μL) (1 L / 10^6 μL) = 2.50×10^(-5) L
(2.50×10^(-5) L) (10 dL / 1 L) = 2.50×10^(-4) dL
(26.7 μg) (1 mg / 1000 μg) = 0.0267 mg
1 ppm = 1 mg/L
( 참고 https://ywpop.tistory.com/5345 )
0.0267 mg / (2.50×10^(-5) L)
= 1068 mg/L
= 1068 ppm
= 1.07×10^3 ppm
0.0267 mg / (2.50×10^(-4) dL)
= 106.8 mg/dL
= 1.07×10^2 mg/dL
[키워드] 25.0 μL 26.7 μg ppm mg/dL 기준, 25.0 μL sample 26.7 μg glucose ppm mg/dL
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