0.105 M CH3COOH 24.0 mL + 0.130 M NaOH. 당량점 부피

0.105 M CH3COOH 24.0 mL + 0.130 M NaOH. 당량점 부피

 

 

24.0 mL of 0.105 M acetic acid (HC2H3O2)

will be titrated with 0.130 M sodium hydroxide (NaOH).

The Ka of acetic acid is 1.77×10^(-5).

b) the volume of added base required to reach the equivalence point

 

 

Consider the titration of a 24.0 mL sample of 0.105 M CH3COOH

with 0.130 M NaOH. What is the volume of added base

required to reach the equivalence point?

 

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▶ 참고: 약산-강염기 적정

[ https://ywpop.tistory.com/2736 ]

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M1V1 = M2V2

산의 mol수 = 염기의 mol수

( 참고 https://ywpop.tistory.com/4689 )

 

(0.105 M) (24.0 mL) = (0.130 M) (? mL)

 

? = (0.105) (24.0) / (0.130)

= 19.38 mL

 

 

 

 

[키워드] CH3COOH NaOH 적정 기준문서, 약산 강염기 적정 기준문서