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화학/원소(연소)분석307

23.46 mg sample 20.42 mg H2O 33.27 mg CO2 23.46 mg sample 20.42 mg H2O 33.27 mg CO2 Ethylene glycol, commonly used as automobile antifreeze, contains only carbon, hydrogen, and oxygen. Combustion analysis of a 23.46 mg sample yields 20.42 mg of H2O and 33.27 mg of CO2. What is the empirical formula of ethylene glycol? What is its molecular formula if it has a molecular weight of 62.0? [참고] CHO 연소분석 [ https://ywpop.tistory.com/2854 ] 간편한.. 2024. 4. 7.
5.0 g Al react 4.45 g O2 5.0 g Al react 4.45 g O2 Aluminum reacts with oxygen to yield aluminum oxide. If 5.0 g of Al reacts with 4.45 g of O2, what is the empirical formula of aluminum oxide? Al의 몰질량 = 26.98 g/mol 이므로, 5.0 g Al의 몰수를 계산하면, 5.0 g / (26.98 g/mol) = 0.185 mol ( 참고 https://ywpop.tistory.com/7738 ) 4.45 g O2의 몰수를 계산하면, 4.45 g / (32.00 g/mol) = 0.139 mol 몰수의 가장 작은 정수비를 계산하면, Al : O2 = 0.185 : 0.139 = 0.185/0... 2024. 4. 7.
unknown liquid H 5.57% Cl 28.01% C 66.42% MW 126.58 unknown liquid H 5.57% Cl 28.01% C 66.42% MW 126.58 An unknown liquid is composed of 5.57% H, 28.01% Cl, and 66.42% C. The molecular weight found by mass spectrometry is 126.58. What is the molecular formula of the compound? [참고] 원소분석 [ https://ywpop.tistory.com/64 ] 시료의 질량 = 100 g 이라 가정하면, 각 성분의 함량(%) = 각 성분의 질량(g) (1) 각 성분의 몰수 계산 > C의 몰수 = 66.42 g / (12.01 g/mol) = 5.53 mol > H의 몰수 = 5.57 / 1... 2024. 4. 7.
45.3 wt% Mg 54.7 wt% Ni 화합물의 화학식 45.3 wt% Mg 54.7 wt% Ni 화합물의 화학식 45.3 wt% Mg와 54.7 wt% Ni로 이루어진 금속간 화합물의 화학식을 구하시오. [참고] 원소분석 [ https://ywpop.tistory.com/64 ] 시료의 질량 = 100 g 이라 가정하면, 시료의 질량% = 시료의 질량(g) Mg의 몰질량 = 24.305 g/mol 이므로, 45.3 g / (24.305 g/mol) = 1.864 mol Mg ( 참고 https://ywpop.tistory.com/7738 ) Ni의 몰질량 = 58.69 g/mol 이므로, 54.7 / 58.69 = 0.932 mol Ni 몰수의 가장 작은 정수비를 계산하면, Mg : Ni = 1.864 : 0.932 = 1.864/0.932 : 0.932/.. 2024. 4. 2.
CHO 연소분석. 1.375 g mannitol 1.993 g CO2 0.9519 g H2O CHO 연소분석. 1.375 g mannitol 1.993 g CO2 0.9519 g H2O A 1.375 g sample of mannitol, a sugar found in seaweed, is burned completely in oxygen to give 1.993 g of carbon dioxide and 0.9519 g of water. The empirical formula of mannitol is: Combustion of a 1.375 g sample of mannitol, a sugar found in seaweed, produced 1.993 g of carbon dioxide (CO2) and 0.9519 grams of water (H2O). What is the empirica.. 2024. 3. 24.
Shattuckite Cu 48.43%, Si 17.12%, O 34.14%, H 0.31% Shattuckite Cu 48.43%, Si 17.12%, O 34.14%, H 0.31% Shattuckite is a fairly rare copper mineral. It has the composition 48.43% copper, 17.12% silicon, 34.14% oxygen, and 0.31% hydrogen. Calculate the empirical formula of shattuckite. [참고] 원소분석 [ https://ywpop.tistory.com/64 ] 시료의 질량 = 100 g 이라 가정하면, 시료의 조성 백분율(%) = 시료의 질량(g) ① 각 성분의 몰수 계산 > Cu의 몰수 = 48.43 g / (63.55 g/mol) = 0.76208 mol ( 참고 htt.. 2024. 3. 20.
30.0 g CHO sample 44.0 g CO2 18.0 g H2O 30.0 g CHO sample 44.0 g CO2 18.0 g H2O 30.0 mg CHO sample 44.0 mg CO2 18.0 mg H2O Upon combustion, a 30.0 g sample of a compound containing only carbon, hydrogen, and oxygen produces 44.0 g of carbon dioxide and 18.0 g of water. Find the empirical formula of the compound. [참고] CHO 연소분석 [ https://ywpop.tistory.com/2854 ] ① 각 성분의 질량 계산 > C의 질량 = 44.0 g × (12/44) = 12.0 g > H의 질량 = 18.0 g × (2/18).. 2024. 3. 17.
hydrocarbon 7.2 g H2O 7.2 L CO2 empirical formula hydrocarbon 7.2 g H2O 7.2 L CO2 empirical formula 어떤 탄화수소 완전연소 시, 7.2 g H2O와 7.2 L CO2가 생성되었다면, 이 탄화수소의 실험식은? The hydrocarbon burns completely, producing 7.2 grams of water and 7.2 liters of CO2 gas at standard condition (1 mole of a gas occupies 22.4 liters at STP). What is the empirical formula of the hydrocarbon? [참고] CH 연소분석. CH 원소분석 [ https://ywpop.tistory.com/9606 ] 탄화수소에 포함된 C 원자는 전부 CO2로.. 2024. 3. 8.
CHO 5.00 g 아세트산 7.33 g CO2, 3.00 g H2O mass 60 CHO 5.00 g 아세트산 7.33 g CO2, 3.00 g H2O mass 60 5.00 g of an organic compound containing C, H and O on combustion yielded 7.33 g CO2 and 3.00 g H2O. If 1 mole of compound weighs 60, then molecular formula of compound is --------------------------------------------------- 답: 실험식 = CH2O, 분자식 = C2H4O2 [Blogger 블로그스팟] [ https://ywpop.blogspot.com/2023/10/cho-500-g-733-g-co2-300-g-h2o-mass-60.html ] [.. 2023. 11. 30.
85.62% C molar mass 84.16 g/mol molecular formula 85.62% C molar mass 84.16 g/mol molecular formula C와 H로만 이루어진 화합물에서 85.62%의 C가 발견되었다. 분자량이 84.16 g/mol이라면 화합물의 분자식을 결정하시오. A compound containing only carbon and hydrogen was found to be 85.62% carbon. Determine the molecular formula of the compound if its molar mass is 84.16 g/mol. --------------------------------------------------- 답: C6H12 [Blogger 블로그스팟] [ https://ywpop.blogspot.com/2023/10/8.. 2023. 10. 31.
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