본문 바로가기
반응형

화학/원소(연소)분석309

CHO 5.048 g sample 7.406 g CO2 3.207 g H2O CHO 5.048 g sample 7.406 g CO2 3.207 g H2O CHO 화합물 시료 5.048 g을 연소시켜 7.406 g CO2와 3.207 g H2O을 얻었다. 이 화합물의 실험식을 계산하여라. The combustion of a 5.048 g sample of a compound of C, H, and O gave 7.406 g of CO2 and 3.027 g of H2O. Calculate the empirical formula of the compound. --------------------------------------------------- ▶ 참고: 원소분석 [ https://ywpop.tistory.com/64 ] ▶ 참고: CH 연소분석 [ https://ywpop.t.. 2021. 4. 16.
CHO 연소분석. 0.2000 g sample 0.2998 g CO2 0.0819 g H2O CHO 연소분석. 0.2000 g sample 0.2998 g CO2 0.0819 g H2O Vitamin C는 괴혈병 예방에 꼭 필요하다. 0.2 g의 CHO 화합물을 연소시켰더니 0.2998 g CO2와 0.0819 g H2O가 생성되었다. 비타민 C의 실험식은? Combustion of a 0.2000 g sample of this C, H, O compound yields 0.2998 g of CO2 and 0.819 g of H2O. Combustion of a 0.2000 g sample of Vitamin C gives 0.2998 g of CO2 and 0.819 g of H2O. What is the empirical formula of Vitamin C? -----------------.. 2021. 4. 14.
2.196 g Cu excess S SO2 gas 2.748 g 5.6 g/cm3 2.196 g Cu excess S SO2 gas 2.748 g 5.6 g/cm3 A copper wire having a mass of 2.196 g was allowed to react with an excess of sulfur. The excess sulfur was then burned, yielding SO2 gas. The mass of the copper sulfide produced was 2.748 g. a) What is the percent composition of copper sulfide? b) What is its empirical formula? c) Calculate the number of copper ions per cubic centimeter if the densi.. 2021. 4. 13.
coniine 5.024 mg sample 13.90 mg CO2 6.048 mg H2O coniine 5.024 mg sample 13.90 mg CO2 6.048 mg H2O Coniine, a toxic substance isolated from poison hemlock, contains only carbon, hydrogen, and nitrogen. Combustion analysis of a 5.024 mg sample yields 13.90 mg of CO2 and 6.048 mg of H2O. What is the empirical formula of coniine? --------------------------------------------------- ▶ 참고: 원소분석 [ https://ywpop.tistory.com/64 ] ▶ 참고: CH 연소분석 [ https:.. 2021. 4. 12.
CH 연소분석. 34.6 mg H2O, 169.2 mg CO2 CH 연소분석. 34.6 mg H2O, 169.2 mg CO2 탄소와 수소로 구성된 벤젠 50.0 mg을 연소 분석하여 34.6 mg의 H2O, 169.2 mg의 CO2를 얻었다. 벤젠의 실험식은 무엇인가? 벤젠의 분자량이 78일 때, 분자식을 구하시오. --------------------------------------------------- ▶ 참고: CH 연소분석 [ https://ywpop.tistory.com/9606 ] ▶ 참고: mass 스펙트럼에서 시료의 분자량 ---> 가장 오른쪽 그룹에 있는 가장 높은 피크의 x축 값 [ https://ywpop.tistory.com/2746 ] 각 성분의 몰수를 계산하면, C의 몰수 = 169.2 × (12/44) / 12 = 3.8455 mol H.. 2021. 4. 12.
조성백분율 C 40.00%, H 6.72%, O 53.29%인 화합물의 분자식 조성백분율 C 40.00%, H 6.72%, O 53.29%인 화합물의 분자식 단, 몰질량 = 180 g/mol --------------------------------------------------- ▶ 참고: 원소분석 [ https://ywpop.tistory.com/64 ] 각 성분의 몰수를 계산하면, 40.00 g / (12 g/mol) = 3.33 mol C 6.72 g / (1 g/mol) = 6.72 mol H 53.29 g / (16 g/mol) = 3.33 mol O 각 성분 몰수의 가장 작은 정수비를 계산하면, C : H : O = 3.33/3.33 : 6.72/3.33 : 3.33/3.33 ≒ 1 : 2 : 1 ---> 실험식 = CH2O ---> 실험식량 = 12 + 2(1) +.. 2021. 4. 9.
phosgene 1.05 atm 25℃ density 4.24 g/L 12.1% C 16.2% O 71.7% Cl phosgene 1.05 atm 25℃ density 4.24 g/L 12.1% C 16.2% O 71.7% Cl Phosgene is a highly toxic gas made up of carbon, oxygen, and chlorine atoms. Its density at 1.05 atm and 25℃ is 4.24 g/L. a) What is the molar mass of phosgene? b) Phosgene is made up of 12.1% C, 16.2% O, and 71.7% Cl. What is the molecular formula of phosgene? --------------------------------------------------- a) M = dRT / P ( 참고.. 2021. 4. 8.
CHO 1.200 g sample 3.516 g CO2 1.007 g H2O CHO 1.200 g sample 3.516 g CO2 1.007 g H2O Anabolic steroids are sometimes used illegally by athletes to increase muscle strength. A forensic chemist analyzes some tablets suspected of being a popular steroid. He determines the substance contains only C, H and O and has a molar mass of 300.42 g/mol. When a 1.200 g sample is subjected to combustion analysis, 3.516 g of CO2 and 1.007 g H2O are col.. 2021. 4. 7.
원소A = 34.59%, 원소B = 61.53%, 원소C = 3.88%의 조성 백분율 원소A = 34.59%, 원소B = 61.53%, 원소C = 3.88%의 조성 백분율 이온 결합 화합물 A(BC)3의 몰질량은 78 g/mol이며, 원소A = 34.59%, 원소B = 61.53%, 원소C = 3.88%의 조성 백분율을 가진다. 계산을 통해 얻어진 각 원소의 원자량을 이용하여 화합물 A(BC)3의 화학식을 쓰고 명명하시오. 가능한 원자의 몰질량(g/mol) Na: 22.99, K: 39.10, Ca: 40.08, Al: 26.98, H: 1.008, C: 12.011, N: 14.0067, O: 15.999, S: 32.065 --------------------------------------------------- A(BC)3 ---> A는 +3가의 금속이므로, A는 Al. ( 참고 .. 2021. 3. 31.
카다베린. 58.55% C, 13.81% H, 27.40% N 102.2 g/mol 카다베린. 58.55% C, 13.81% H, 27.40% N 102.2 g/mol 카다베린은 C 58.55%, H 13.81%, N 27.40%의 질량 백분율 몰질량 = 102.2 g/mol Determine the empirical and molecular formula Cadaverine, a foul-smelling substance produced by the action of bacteria on meat, contains 58.55% C, 13.81% H, and 27.40% N by mass; its molar mass is 102.2 g/mol. --------------------------------------------------- ▶ 참고: 원소분석 [ https://ywpop.t.. 2021. 3. 24.
반응형